Question

(x²–2x/x²+2x) = (3x +6/ x–2)
please explain....​

Answer 1

Step-by-step explanation:

${x}^{2} - 2x \div {x}^{2} + 2x = 3x + 6 \div x - 2 \\ (x(x - 2) \div x(x + 2)) = 3x + 6 \div x - 2 \\ x - 2 \div x + 2 = 3x + 6 \div x - 2 \\ {(x - 2) }^{2} = (3x + 6)(x + 2) \\ {x}^{2} - 2x + 4 = 3 {x}^{2} + 6x + 6x + 12 \\ {x}^{2} - 2x + 4 = 3 {x}^{2} + 12x + 12 \\ 3 {x}^{2} - {x}^{2} + 12x + 2x + 12 - 4 = 0 \\ 2 {x}^{2} + 14x - 8 = 0 \\ {x}^{2} + 7x - 4 = 0$