x²+2x²+1+3(x²+1) factorise
Answers
Answered by
0
x
2
+
x
2
1
+2−2x−
x
2
=(x+
x
1
)(x+
x
1
−2)
Step-by-step explanation:
\begin{gathered}Given ,\\x^{2}+\frac{1}{x^{2}}+2-2x-\frac{2}{x}\end{gathered}
Given,
x
2
+
x
2
1
+2−2x−
x
2
=x^{2}+\frac{1}{x^{2}}+2\times x \times \frac{1}{x}-2x-\frac{2}{x}=x
2
+
x
2
1
+2×x×
x
1
−2x−
x
2
=\big(x+\frac{1}{x}\big)^{2}-2\big(x+\frac{1}{x}\big)=(x+
x
1
)
2
−2(x+
x
1
)
=\big(x+\frac{1}{x}\big)\big(x+\frac{1}{x}-2\big)=(x+
x
1
)(x+
x
1
−2)
Therefore,
\begin{gathered}x^{2}+\frac{1}{x^{2}}+2-2x-\frac{2}{x}\\=\big(x+\frac{1}{x}\big)\big(x+\frac{1}{x}-2\big)\end{gathered}
x
2
+
x
2
1
+2−2x−
x
2
=(x+
x
1
)(x+
x
1
−2)
Answered by
0
Answer : x² + 2x² + 1 + 3( x² +1)
- 3x²+ 1 + 3x² + 3 = 0
- 6x² + 4 = 0
- (√6x + 4) (√6x - 4) = 0
- √6x + √4 = 0 or √6x - √4 = 0
- √6x = -√4. or. √6x = √4
- x = -√4/√6. or. x = √4/√6
- x = -√2/√3. or. x = √2/√3
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