Question

x² + 2xy + y ² - 1
use identities​

Answer 1

Answer:

(x^2+2xy+y^2) - 1

(x+y) ^2 - (1^2)

(x+y+1) (x+y-1)

by using (a^2-b^2) =(a+b) (a-b)

(a+b) ^2= a^2+ b^2+2ab