x²+2xy+y²-200x-200y+1900=0
How many solutions (x,y) are there?
*x and y are integer numbers between 1 and 100 (inclusive).
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Answer: the value of xy is 1
x+y=2 and x²+ y²=2
then
(X+y)²= x²+2xy+y²
2²= x²+ y²+2xy
4=2+2xy
4-2=2 xy
2=2xy
Therefore xy=2/2=1
Step-by-step explanation:
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