Question

x2 + 2xy + y2 - a2 - 2ab + b2

Answer 1

Heya user☺☺

(x^2 +2xy +y^2) - (a^2 + b^2 -2ab)

(x+y)^2 - (a-b)^2

Using identity of a^2 - b^2 = (a+b)(a-b), we have

(x+y+a-b)(x+y-a+b)

Hope it will help☺☺

Answer 2

Answer:

(a+y+a−b)(a+y−a+b)

Step-by-step explanation:

Given : x

2

+2xy+y

2

−a

2

+2ab−b

2

Considering x

2

+2xy+y

2

−a

2

+2ab−b

2

We can further write it as

=(x

2

+2xy+y

2

)−(a

2

−2ab+b

2

)

So we get

=(x+y)

2

−(a−b)

2

Based on the equation a

2

−b

2

=(a+b)(a−b)

We get

=[(x+y)+(a−b)][(x+y)−(a−b)]

x

2

+2xy+y

2

−a

2

+2ab−b

2

=(a+y+a−b)(a+y−a+b)

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