Question

x² - 2xy + y² - z²

factorise the following also give steps​

Answer 1

Answer:

x-y-z

Step-by-step explanation:

x²-2xy+y²=z²

(x-y)²=z²

taking roots on both the sides

we get

x-y=z

which gives the final answer

x-y-z

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Answer 2

Step-by-step explanation:

x² - 2xy + y² - z²

= $(x)^{2}$ - 2×x×y + $(y)^{2}$ - $z^{2}$          [∵$a^{2} - 2ab + b^{2} = (a-b)^{2}$]

= $(x-y)^{2}$ - $z^{2}$       [∵ $a^{n}- b^{n} = (a-b)^{n}$]

=  $(x-y-z)^{2}$ (Ans)