Question

(x2-2xy+y2)-z2 how should i solve it

Answer 1

hello Frnd

here is your answer

Given as
$( {x}^{2} - 2xy + {y}^{2} ) - {z}^{2} \\ \\ > > {(x - y)}^{2} - {z}^{2} \\ \\ > > ((x - y) + z)((x - y) - z) \\ > > (x - y + z)(x - y - z) \\ {x}^{2} - xy - xz - xy + {y}^{2} + yz + xz - zy - {z}^{2} \\ \\ \\ \\ \\ \\ hope \: it \: helps \:$

Answer 2

Answer:

( x- y + z ) ( x- y- z)

Step-by-step explanation:

( x2 - xy - xy + y2 ) - z2

( x(x-y) - y ( x-y ) ) -z2

( ( x-y ) ( x-y) ) - z2

( x- y2) - z2

x- y + z ) ( x- y- z)