Question

( x2-2y2-3z2)2 expand​

Answer 1

Answer:

formula

(x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2zx

(x^2-2y^2-3z^2)^2

=x^4+4y^4+9z^4+(2*x^2*-2y^2)+(2*-2y^2*-3z^2)+(2*-3z^2*x^2)

=x^4+4y^4+9z^4-8x^2y^2+12y^2*z^2-6x^2z^2

hope it helps..