x²-[2y²+x²-{-3x²+5y²-(x²-3+y²)}]-(4x²+2y²+3)
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0
Answer:
- 2y²
Step-by-step explanation:
x² ( 3- 5y² ) + x ( xy² - 3x ) -2y ( y - 2x² y )
=>
3x² - 5x²y² + x²y² - 3x² - 2y² + 4x² y²
=>
{ 3x² - 3x² } + { 5x²y² - 5x²y² } - 2y²
=>
0 + 0 - 2y²
=>
= - 2y²
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