Question

x² + (√3+1)x+√3=0
Solve for x completing the square ​

Answer 1

Step-by-step explanation:

x^2+(√3+1)x+√3

x^2+(√3+1)x+√3=x^2+√3x+1x+√3

x^2+(√3+1)x+√3=x^2+√3x+1x+√3=x(x+√3)+1(x+√3)

x^2+(√3+1)x+√3=x^2+√3x+1x+√3=x(x+√3)+1(x+√3)=(x+1) (x+√3)

x^2+(√3+1)x+√3=x^2+√3x+1x+√3=x(x+√3)+1(x+√3)=(x+1) (x+√3)x+1=0. | x+√3=0

x^2+(√3+1)x+√3=x^2+√3x+1x+√3=x(x+√3)+1(x+√3)=(x+1) (x+√3)x+1=0. | x+√3=0or,x=–1. | or,x=–√3

SOMETHING IS WRONG WITH THE EQUATION

becoz both the value of "x" will not be in minus(–)