Question

x²-(✓3+1)x+✓3 plZzzzzzzzzzzzzz9zzzzzzz​

Answer 1

Answer:

x2 -(in root 3+1)x+in root 3

x2 - in root 3x - x + in root 3

x (x- in root 3 )-1 (x - in root 3)

x-in root 3 = 0 or x-1 =0

x = in root 3 or x = 1

are the root of given quadratic equation