Question

x²-(√3+1)x+√3 to find the zeros of polynomial
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Answer 1

Answer:

x=1,√3

Explanation:

0=x²-(√3+1)x+√3

0=x²-√3x-x+√3

0=x(x-1)-√3(x-1)

0=(x-√3)(x-1)

∴x=√3,1