Math, asked by krishna9212730390, 3 months ago

x² + 3√2x +4 factorise the given term​

Answers

Answered by anindyaadhikari13
3

Solution:

We have to factorise - x² + 3√2x + 4. To do this, we have to split the middle term.

By splitting the middle term, we get,

= x² + √2x + 2√2x + 4

Taking x and 2√2 as common, we get,

= x(x + √2) + 2√2(x + √2)

Taking (x + √2) as common, we get,

= (x + √2)(x + 2√2) which is our required answer.

Answer:

  • (x + √2)(x + 2√2)

•••♪

Answered by tennetiraj86
4

Step-by-step explanation:

Given :-

X^2 + 3√2 X + 4

To find:-

Factorise the expression X^2 + 3√2 X + 4

Solution:-

Given expression is X^2 + 3√2 X + 4

=>X^2+√2X +2√2X + 4

=>X^2+√2X+2√2X+(√2×2√2)

=>X(X+√2) +2√2(X+√2)

=>(X+√2)(X+2√2)

Therefore,X^2 + 3√2 X + 4 = (X+√2)(X+2√2)

Answer:-

Factorization of X^2 + 3√2 X + 4 is

(X+√2)(X+2√2)

Check:-

(X+√2)(X+2√2)

=>X(X+2√2)+√2(X+2√2)

=>X^2+2√2X+√2X+√2×2√2

=>X^2+3√2X+4

Verified the given relation.

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