Question

x² ( 3 - 2x + x² ) for x = 1; x = -1; x = 2/3 and x = -1/2
please it is urgent​

Answer 1

Answer:

if x = 1

then x²(3-2x+x²)

= 1(3-2 +1)

= 1×0 = 0

IF x = -1

then x²(3-2x + x²)

=-1²{3-(-2) + (-1)²}

= 1(3+2 + 1)

= 6

it x = 2/3 then

x²(3-2x+x²)

= (2/3)² { 3- 2× 2/3 + (2/3)² }

= 4/9( 3- 4/3 + 4/9)

= 4/9( 19/9)

= 4/9 × 9/19

= 4/19

if x = -1/2

then,

x²(3-2x+ x²)

= (-1/2)²{3- 2(-1/2) + (-1/2)²}

= 1/4( 3+1 + 1/4}

= 1/4( 17/4)

= 1/4×4/17

= 1/17

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Answer 2

Step-by-step explanation:

x² ( 3 - 2x + x² )

when x=1,x² ( 3 - 2x + x² )

=x1 ( 3 - 2+ 1 )

=1 ( 1+ 1 )

=2

x=-1. x² ( 3 - 2x + x² )

=-1² ( 3 - 2*1 + -1² )

=-1 ( 3 - 2+ 1)

=-1(2)

= - 2

x=2/3. x² ( 3 - 2x + x² )

=(2/3)² ( 3 - 2(2/3)+ (2/3)² )

=(4/9)(3-4/3+4/9)

=(4/9)(19/9)

=76/81

x=-1/2 , x² ( 3 - 2x + x² )

=(-1/2)² ( 3 - 2(-1/2) + (-1/2)² )

=(1/4)(3+1+(1/4))

=(1/4)(4 1/4)

=4 1/2