Question

X2-3√3x+9=0 ayuda :(

Answer 1

Step-by-step explanation:

I hope that the answer will help you thank you

Answer 2

Answer:

${x}^{2} - 3 \sqrt{3} x + 9 = 0$

D = b^2 -4ac

$= { (- 3 \sqrt{3} )}^{2} - 4 \times 1 \times 9 \\ = 27 - 36 \\ = - 9$

D is negative roots does not exist.