Question

x²-3√5 x + 10 = 0
Answer: √5 and 2√5​

Answer 1

ANSWER:

• value of x = √5 and 2√5

GIVEN:

• P(x) = x²-3√5x+10 = 0

TO FIND:

• Value of 'x'

SOLUTION:

=> x²-3√5x+10 = 0

=> x²-√5x-2√5x+10 = 0

=> (x²-√5x) +(-2√5x+10) = 0

=> x(x-√5) -2√5(x-√5) =0

=> (x-√5)(x-2√5) =0

Either;. (x-√5) =0

=> x-√5 = 0

=> x = √5

Either (x-2√5) = 0

=> x-2√5 = 0

=> x = 2√5

So value of x = √5 and 2√5

In this way we can factorise the equation and find the solution.

NOTE:

some important formulas:

• (a+b)(a-b) = a²-b²
• (a+b)² = a²+b²+2ab

Answer 2

Answer:

Given:

We have been given a quadratic polynomial x²-3√5 x + 10

To Find:

We need to find the value of x.

Solution:

We can find the value of x by splitting the middle term.

x²-3√5 x + 10 = 0

=> x²-√5 x -2√5 x + 10 = 0

=> (x²-√5 x) -2√5(x -√5) = 0

=> (x -√5)(x-2√5 ) = 0

Therefore either x -√5 = 0 or x-2√5 = 0.

When x -√5 = 0

=> x -√5 = 0

=> x =√5

When x-2√5 = 0

=> x-2√5 = 0

=> x = 2√5

Hence, the values of x are √5 and 2√5.