(x²+3) is a factor of 2x⁶ +6x⁴ - x³+5x²-3x+15.
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Answered by
2
Answer:
Let f(x)=x
3
−2x
2
−5x+6
⇒f(1)=1
3
−21
2
−5×1+6=1−2−5+6=0
Using synthetic division, we have
x
2
−x−6=0 is the other factor
(x−1)(x
2
−x−6)=0
=(x−1)(x
2
−3x+2x−6)=0
=(x−1)(x(x−3)+2(x−3))=0
=(x−1)(x+2)(x−3) are the factors of f(x)
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0
Answer:
https://brainly.in/question/9740809?referrer=searchResults
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