Question

x²- (3 root 2 - 2i) x-6 root 2 i = 0

CLASS 11 COMPLEX NUMBERS​

Answer 1

Answer:

3√2, 2i

Step-by-step explanation:

Given as x² – (3√2 + 2i)x + 6√2i = 0

x²– (3√2x + 2ix) + 6√2i = 0

x²– 3√2x – 2ix + 6√2i= 0

x(x – 3√2) – 2i(x – 3√2)= 0

(x – 3√2) (x – 2i)= 0

(x – 3√2) = 0 or (x – 2i) = 0

x = 3√2 or x = 2i

∴ The roots of the given equation are 3√2, 2i

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Answer 2

Step-by-step explanation:

X^2-(3√2–2i)x-6√2i=0

X^2–3√2x+2ix-6√2i=0

X(x-3√2)+2i(x-3√2)=0

(X+2i)(x-3√2)=0

If

X+2i=0

X=-2i

if

X-3√2=0

X=3√2