Question

x²- (3 root 2 - 2i) x-6 root 2 i = 0 CLASS 11 COMPLEX NUMBERS​

Answer 1

✪ Answer:

x = 3√2 or 2i

❒ Step-by-step explanation:

Given Quadratic equation → x² - (3√2 - 2i)x - 6√2i = 0

On opening the brackets;

x² - 3√2x - 2ix + 6√2i = 0

Rearranging the terms,

➝ x - 2ix - 3√2x + 6√2i = 0

⇒ x (x - 2i) - 3√2 (x - 2i) = 0

➾ (x - 3√2) (x - 2i) = 0

Now equate each factor to zero to find the value of x.

x - 3√2 = 0

⇒ x = 3√2

Also,

x - 2i = 0

⇒ x = 2i

Hence, the values of x are: 3√2 or 2i

Answer 2

$\sf\huge\bold{Answer:}$

Given :

• Quadratic equation : x²-3√2-2i)x-6√2i=0

To find :

Roots of given equation

Solution :

→ x²-(3√2-2i)x-6√2i=0

• Opening bracket

→ x²-3√2x+2ix-6√2i=0

→ x²+2i-3√2x-6√2i=0

• Taking out common terms

→ x(x+2i)-3√2(x+2i)=0

→(x-3√2)(x+2i)=0

• Comparing each term with zero

→ x-3√2 = 0 $\:\:\:$ →x+2i = 0

→ x = 3√2 $\:\:\:$→ x = -2i

Roots of Given Complex Quadratic Equation are 3√2 and -2i