Question

(x²+3/x)^5 expand using binomial therom​

Answer 1

Answer:

(x−3)5=x5−15x4+90x3−270x2+405x−243. Explanation: The Binomial Theorem Expansion :)5=x5+5C1x4(−3)1+5C2x3(−3)2+5C3x2(−3)3+5C4x1(−3)4+(−3)5. Here, 5C1=5C5−1=5C4=5,5C2=5C3=5⋅41⋅2=10 So, (x−3)5=x5+5x4(−3)+10x3(9)+10x2(−27)+5x(81)+(−243). =x5−15x4+90x3−270x2+405x−243