Question

x²
3rt 6
Solve for "x"
if log
I
2
2
$solve for x if log_{2}(x }^{2} { - 3x + 6 = 2)$
​

Answer 1

Given:

• A logarithm to us.
• The logarithm is $\sf{log_{2}^{x^{2}-3x+6}=2}$

To Find:

• The value of x .

Solution:

Given logarithm to us is ,

$\sf{\implies log_{2}^{x^{2}-3x+6}=2}$

$\sf{\implies 2^{2}=x^{2}-3x+6}$

$\sf{\implies 4=x^{2}-3x+6}$

$\sf{\implies x^{2}-3x+6-4=0}$

$\sf{\implies x^{2}-3x+2=0}$

$\sf{\implies x^{2}-2x-x+2=0}$

$\sf{\implies x(x-2)-1(x-2)=0}$

$\sf{\implies (x-1)(x-2)=0}$

${\underline{\underline{\boxed{\red{\sf{\leadsto x =2,1}}}}}}$