Question

x2-3x -1=0 find factors of the quadratic equation

Answer 1

By the Formula $(-b (+/-) \sqrt{b^2 - 4ac}) /2a$
Substituting a=1,b=-3,c=-1
We get
$x_{1}= 3+ \sqrt{13}$
and
$x_{2} =3- \sqrt{13}$
So,($(x-3- \sqrt{13}) (x-3+ \sqrt{13})=x^2-3x-1$)