Question

x² – 3x + 1=0 solve this problem in quadratic equation​

Answer 1

The formula for the discriminant of a quadratic equation is

D=b^2−4ac

Substituting values for a, b and c

D=(-3)^2-4×1×1

D=9-4

D=5

Now, the formula for finding 'x' using the discriminant is

x=( −b±√D)/2a

Substituting values for b, D and a in the above formula, you get

x=(3±√5)/2

Hence, the values for 'x' are

x=(3+√5)/2 and (3−√5)/2.

Answer 2

Step-by-step explanation:

x^2−3x+1=0

Considering the coefficients and constants in the equation

a=1 [Coefficient of x^2]

b= -3 [Coefficient of x]

c = 1 [The constant term]

The formula for the discriminant of a quadratic equation is

D=b^2−4ac

Substituting values for a, b and c

D=(−3)^2−4×1×1

D=9−4

D=5

Now, the formula for finding 'x' using the discriminant is

x = (−b±√D)/2a

Substituting values for b, D and a in the above formula, you get

x = (3±√5)/2

Hence, the values for 'x' are

x = (3+√5)/2 and (3−√5)/2