Question

x2+3x+1=(x-2)2
$x {}^{2} + 3x + 1 = (x - 2) {}^{2}$
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Answer 1

Answer:

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Answer 2

$\huge\tt{\bold{\underline{\underline{Question᎓}}}}$

$x {}^{2} + 3x + 1 = (x - 2) {}^{2}$

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

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$= > {x}^{2} + 3x + 1 = {(x - 2)}^{2}$

$= > {x}^{2} + 3x + 1 = {x}^{2} + 4 - 4x$

Here,we see that x square lies on both side of the equation so it gets cancelled :-

$= > 3x + 1 = 4 - 4x$

=>separate out variable terms together and constant terms together to make our calculation easier:-

$= > 3x + 4x = 4 - 1$

$= > 7x = 3$

$\bold{\red{= > x = \frac{3}{7}}}$

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