Question

x² - 3x - 10 = 0 solve the following equation by factorisation​

Answer 1

GIVEN :-

• x² - 3x - 10

TO FIND :-

• The value of x by factorization.

SOLUTION :-

➬ x² - 3x - 10 = 0

☯ By splitting the middle term ,

➬ x² - 5x + 2x - 10 = 0

➬ x(x - 5) + 2(x - 5) = 0

➬ (x + 2) , (x - 5) = 0

➬ x + 2 = 0 , x - 5 = 0

➬ x = -2 , x = 5.

Hence the value of x = -2 and 5.

VERIFICATION :-

☯ For x = -2

➬ x² - 5x + 2x - 10 = 0

➬ (-2)² - 5 × (-2) + 2 × (-2) - 10 = 0

➬ 4 + 10 - 4 - 10 = 0

➬ 4 - 4 + 10 - 10 = 0

➬ 0 + 0 = 0

➬ 0 = 0

L.H.S = R.H.S

☯ For x = 5

➬ x² - 5x + 2x - 10 = 0

➬ (5)² - 5 × 5 + 2 × 5 - 10 = 0

➬ 25 - 25 + 10 - 10 = 0

➬ 0 + 0 = 0

➬ 0 = 0

L.H.S = R.H.S

HENCE VERIFIED ✔

Answer 2

ANSWER✔

$\large\underline\bold{GIVEN,}$

$\sf\large\therefore x^2-3x-10$

$\large\underline\bold{TO\:FIND,}$

$\sf\dashrightarrow values\:of\:x\:by\:factorusation$

$\large\underline\bold{SOLUTION,}$

$\sf\therefore x^2-3x-10=0$

$\sf\implies x^2-5x+2x-10=0$

$\sf\implies x \times (x-5)+2 \times (x-5)=0$

$\sf\implies (x+2)(x-5)=0$

$\sf\implies (x+2)=0 \:and\:(x-5)=0$

$\sf\implies x= -2 \:and\: x=5$

$\sf\implies x=-2,5$

$\large{\boxed{\bf{ x=-2,5}}}$

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