Question

x²-3x-10 factorize bas yeh nikal ke dedo​

Answer 1

Answer:

(x+2)(x-5)

Step-by-step explanation:

Given

= x²-3x-10

= x²-5x+2x-10

= x(x-5)+2(x-5)

= (x+2)(x-5)

Answer 2

Question:

Factorise: x²-3x-10

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Steps to factorise the middle term:

Before moving on to the answer, let's first understand the steps to split the middle term.

☆ Find the product of the first and the last term. (we can ignore the variable)

$\sf \green {x² \times 10 = 10}$

☆ Find the factors of the product so obtained.

$\sf \green {1 \times 10}$

$\sf \green {2 \times 5}$

☆ Find the two numbers such that their product is equal to the product of first and last term and their sum or difference is equal to the middle term.

$\sf \green {5 \times 2 = 10\ and\ 5-2 =3}$

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Solution:

Here, we will use the method of splitting the middle term.

So,

x²-3x-10

$\implies {x²-(5-2)x-10}$

$\implies {x²-5x+2x-10}$

$\bigstar {\sf {\red {Grouping\ the\ terms}}}$

$\implies {(x²-5x)+(2x-10)}$

$\bigstar {\sf {\red {Taking\ out\ common\ from\ each\ group.}}}$

$\implies {x(x-5)+2(x-5)}$

$\implies {(x-5)(x+2)}$

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Final answer:

$\boxed {\sf {\pink {Factorised\ form\ of\ x²-3x-10\ is\ (x-5)(x+2)}}}$