Math, asked by vicky3948, 3 months ago

x2 + 3x-10 में x के शून्यांक क्या हैं​

Answers

Answered by sharanyalanka7
4

Step-by-step explanation:

\huge\bf\underline\blue{answer}

given,

x²+3x-10

to find :-

value of 'x'

let's understand:-

to find the value of x first we need to factorise the expression in splitting the middle term or by formula of finding roots of the expression.

required formula:

x =    \frac{ - b + (or) -  \sqrt{ {b}^{2} - 4ac } }{2a}

\huge\fcolorbox{black}{purple}{solution}

  • Method 1 :-

{splitting the middle term}

x²+3x-10 = 0

x²+5x-2x-10 = 0

(x+5)(x-2) = 0

.: equate the both terms to zero.

x + 5 = 0. x-2 = 0

x = -5. x = 2

.: the value of x = -5,2.

method 2:-

{formula based}

now let's compare the equation 'x²+3x-10 = 0'

with ax²+bx+c = 0

.: a = 1

b= 3

c = -10

.: substituting values in formula.

      \frac {  - 3 + (or) - \sqrt{ {3}^{2} - 4 \times 1 \times ( - 10) } }{2 \times 1}

  \frac {  - 3 + (or) - \sqrt{9 + 40} }{2}

  \frac{  - 3 + (or) - \sqrt{49} }{2}

 \frac{ - 3 + (or) - 7}{2}

 \frac{ - 3 + 7}{2} (or) \:  \frac{ - 3 - 7}{2}

 \frac{4}{2} (or) \frac{ - 10}{2}

2(or) - 5

.: x = 2,-5

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