x2 + 3x - 18= 0 factors
Answers
Answered by
1
See the attach file for ur ans
Attachments:
Answered by
1
Using dharacharya formula
x = ( -b(+-) root b^2-4ac)/ 2a
x = ( -3(+-)root 9-4(1)(-18) )/2
x = ( -3(+-)9 )/2
x = 3 or x= -6
hence factor is
(x-3)(x+6) = 0
x = ( -b(+-) root b^2-4ac)/ 2a
x = ( -3(+-)root 9-4(1)(-18) )/2
x = ( -3(+-)9 )/2
x = 3 or x= -6
hence factor is
(x-3)(x+6) = 0
Similar questions