(x²+3x)²-2(x²+3x)-8=0
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Answer:
(x²+3x)²-2(x²+3x)-8=0
=> x^4 +3x^2 -2x^2+3x=8
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Here is your answer
Step-by-step explanation:
Given
(x^2 + 3x)^2 - 2(x^2 + 3x) - 8 = 0
Prove
(x^4 + 9x^2) - 2x^2 - 6x - 8 = 0
x^4 + 7x^2 - 6x - 8 = 0
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