Question

.x2-3x + 2 by x-1. .​

Answer 1

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Answer 2

Answer:

x-2

To Find:

• Value of $\tt{\dfrac{x^{2}-3x+2}{x-1}}$

☸Solution☸

• Firstly we have to factorise numerator.

$\longrightarrow\sf{\dfrac{x^{2}-2x-x+2}{x-1}}$

$\longrightarrow\sf{\dfrac{x(x-2)-1(x-2)}{x-1}}$

$\longrightarrow\sf{\dfrac{(\cancel{x-1})(x-2)}{\cancel{x-1}}}$

• Now, after cancelling x-1 from numerator and denominator, we get

$\longrightarrow\sf{\purple{x-2}}$

➺Hence, the value of $\tt{\dfrac{x^{2}-3x+2}{x-1}}$ is $\bf{\green{x-2}}$.