Question

√x2 + 3x + 2 < 1 + √x2 - x + 1​
solve this inequality

Answer 1

Step-by-step explanation:

$\sqrt{ {x}^{2} } + 3x + 2 < 1 + \sqrt{ {x}^{2} } - x + 1$

$x + 3x + 2 < 1 + x - x + 1$

$4x + 2 < 1$

$4x < - 1$

$x < \frac{ - 1}{4}$

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Answer 2

Answer:

X<O is the answer.

Step-by-step explanation:

For explaination see the attached image...

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