Question

x²+3x+2 then the value of alpha square and beta square​

Answer 1

Answer:

Given equation : $x^{2} +3x+2=0$

=> $x^{2} +2x+x+2=0$

=> $x(x+2)+1(x+2)=0$

=> (x+1)(x+2) = 0

=> α = -1 (or) -2 ; β = -1 (or) -2

Therefore $\alpha ^2+\beta ^2= (-1)^2+(-2)^2$

=>1 + 4 =5

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Answer 2

Answer:

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Step-by-step explanation:

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