Question

x²–3x–4=0 completing the square

please help me i have urgent
10th standard question​

Answer 1

Step-by-step explanation:

Let x1 and x2 be the 2 roots

their sum is x1+x2=2 (1)

Their product is (x1)(x2)=-143 (2)

Square both sides of (1)

x1^2+2x1x2+x2^2=4

x1^2+x2^2=4–2(x1)(x2)

Use (2)

x1^2+x2^2=4–2(-143)

x1^2+x2^2=4+286

x1^2+x2^2=290

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Add 4 to both sides of the equation.

x²−3x=4

To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of b.

(b/2)²=(− 3/2)²

Add the term to each side of the equation.

x²−3x+(− 3/2)²=4+(− 3/2)²

Simplify the equation.

x²−3x+9/4=25/4

Factor the perfect trinomial square into(x−3/2)².

(x−3/2)²=25/4

Solve the equation for x.

x=4,−1

Answer 2

Answer:

x=4 or -1 is your answer TQ Mark as brainlist