(x2-3x + 7) x (2x + 3) give answer
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Step-by-step explanation:
(x2-3x + 7) x (2x + 3)
= 2x(x2-3x + 7) +3(x2-3x + 7)
= 2x(x2-3x + 7) +3(x2-3x + 7)
= 2x^3 -6x^2 +14x +3x^2 -9x +21
= 2x(x2-3x + 7) +3(x2-3x + 7)
= 2x^3 -6x^2 +14x +3x^2 -9x +21
= 2x^3 -3x^2 +5x +21
= 2x(x2-3x + 7) +3(x2-3x + 7)
= 2x^3 -6x^2 +14x +3x^2 -9x +21
= 2x^3 -3x^2 +5x +21
This is your answer
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