Question

x²+3x+9=o give me anshwer

Answer 1

Given,

$x^{2} + 3x +9 = 0 \\ \\ comparing \ with \ ax^{2} + bx + c = 0 \\ \\ We \ get, \ \\ \\ a = 1 \\ \\ b = 3 \\ \\ c = 9 \\ \\ So, \\ \\ x = \frac{-b\frac{+}{}\sqrt{b^{2}- 4ac}}{2a} \\ \\ x = \frac{-3\frac{+}{}\sqrt{3^{2}- 4*1*9}}{2*1} \\ \\ x = \frac{-3\frac{+}{}\sqrt{9-36}}{2} \\ \\ x = \frac{-3\frac{+}{}\sqrt{-27}}{2} \\ \\ x = \frac{-3\frac{+}{}3\sqrt{3}\ i}{2} \ Ans.$