Question

(x2+3x+9)÷(x-3)
divide and write quotient and the remainder​

Answer 1

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Answer 2

The quotient is x+6 and remainder is 27.

Given:

• $( {x}^{2} + 3x + 9) \div (x - 3)$

To find:

• Find quotient and the remainder.

Solution:

Concept to be used: Perform long division.

Step 1:

Let

$p(x) = {x}^{2} - 3x + 9$

and

$g(x) = x - 3$

Step 2:

Multiply g(x) with constant or expression so that it's first term will be equal to p(x).

$\:\:\:x - 3 \: ) \: {x}^{2} + 3x + 9 \: ( \: x + 6 \\ {x}^{2} - 3x \\ ( - ) \: \: \: ( + ) \\ - - - - - \\ 6x + 9 \\ 6x - 18 \\ ( - ) \: ( + ) \\ - - - - - \\ 27 \\ - - - - -$

Thus,

Quotient of division is x+6.

Remainder is 27.

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