Math, asked by priyanshu3512, 1 year ago

x2+3x-(a2+a-2) = 0 find the roots of given polynomial

Anonymous: a2 means a^2? plz write the proper correct question here in the comments !

priyanshu3512: ya a^2

Anonymous: write the full question here then I can answer it plz

Anonymous: at least write the polynomial

priyanshu3512: x^2+3x-(a^2+a-2)

Anonymous: ok

Answers

Answered by Anonymous

109

Given :

x² + 3 x - ( a² + a - 2 ) = 0

==> x² + 3 x - ( a² + 2 a - a - 2 ) = 0

==> x² + 3 x - ( a ( a + 2 ) - 1 ( a + 2 ) ) = 0

==> x² + 3 x - ( a + 2 )( a - 1 ) = 0

==> x² + ( ax + 2 x - ax + x ) - ( a + 2 )( a - 1 ) = 0

==> x² + x( a + 2 ) - x ( a - 1 ) - ( a + 2 )( a - 1 ) = 0

==> x ( x + a + 2 ) - ( a - 1 ) ( x + a + 2 )

==> ( x + a + 2 )( x - a + 1 ) = 0

Either

x + a + 2 = 0

==> x = - a - 2

x - a + 1 = 0

==> x = a - 1

The roots are :

x = - a - 2

x = a - 1

Hope it helps:-)

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priyanshu3512: its is a right answer

Anonymous: thanks :-)

Answered by prasannarv2001

Answer:

Step-by-step explanation:

x² + 3 x - ( a² + a - 2 ) = 0

x² + 3 x - ( a² + 2 a - a - 2 ) = 0

x² + 3 x - ( a ( a + 2 ) - 1 ( a + 2 ) ) = 0

x² + 3 x - ( a + 2 )( a - 1 ) = 0

x² + ( ax + 2 x - ax + x ) - ( a + 2 )( a - 1 ) = 0

x² + x( a + 2 ) - x ( a - 1 ) - ( a + 2 )( a - 1 ) = 0

x ( x + a + 2 ) - ( a - 1 ) ( x + a + 2 )

( x + a + 2 )( x - a + 1 ) = 0

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