Question

x²+3x-(a²+a-2) =0
solve in factorization method
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Answer 1

ans is right ☝☝☝☝☝ .. thanks

Answer 2

Answer:

Given:

x²+3x-(a²+a-2)=0

x²+3x-(a²+2a-a-2)=0

x²+3x-(a(a+2)-1(a+2))=0

x²+3x-(a+2)(a-1)=0

x²+x(ax+2x-ax+x)-(a+2)(a-1)=0

x²+x(a+2)-x(a-1)-(a+2)(a-1)=0

x(x+a+2)-(a-1)(x+a+2)

(x+a+2)(x-a+1)=0

Either

x+a+2=0

x=-a-2

Or

x-a+1=0

x=a-1

The roots are:-

x=-a-2

x=a-1

I Hope It Helps :-)