Question

x² - 3x - m (m+3)(a)m,m+3​

Answer 1

Answer:

f(x) = x2 – 3x – m (m + 3) By adding and

subtracting

mx, we get f(x) = x2 – mx – 3x + mx – m (m + 3) = x

[x – (m + 3)] + m[x – (m + 3)] = [x – (m + 3)] (x + m) f(x) = 0 ⇒ [x – (m + 3)] (x + m) = 0 ⇒ [x – (m + 3)] = 0 or (x + m) = 0 ⇒ x = m + 3 or x = –m So, the zeroes of f(x) are –m and +3.Read more on Sarthaks.com - https://www.sarthaks.com/129532/find-the-zeroes-of-the-polynomial-x-2-3x-m-m-3

Step-by-step explanation:

@MNF

Answer 2

Answer:

x^2 - 3x - m(m+3) = 0

x^2 - 3x - m(m+3) = 0=> x^2 + mx - (m+3)x- m(m+3) = 0

x^2 - 3x - m(m+3) = 0=> x^2 + mx - (m+3)x- m(m+3) = 0=> x(x+m) - (m+3)(x+m) = 0

x^2 - 3x - m(m+3) = 0=> x^2 + mx - (m+3)x- m(m+3) = 0=> x(x+m) - (m+3)(x+m) = 0=> (x+m) (x-m-3) = 0

x^2 - 3x - m(m+3) = 0=> x^2 + mx - (m+3)x- m(m+3) = 0=> x(x+m) - (m+3)(x+m) = 0=> (x+m) (x-m-3) = 0x = - m and m+3

x^2 - 3x - m(m+3) = 0=> x^2 + mx - (m+3)x- m(m+3) = 0=> x(x+m) - (m+3)(x+m) = 0=> (x+m) (x-m-3) = 0x = - m and m+3Roots are - m and m+3

Step-by-step explanation:

@darksoul