Question

x²+3x+x+3-(x²+4x)÷x²+3x+4x+12​

Answer 1

Answer:

$= > \frac{ ({x}^{2} + 3x + x + 3) ( {x}^{2} + 4x) }{ ({x}^{2} + 3x + 4x + 12 )} \\ = > \frac{ (x(x + 3) + 1(x + 3))(x(x + 4))}{(x(x + 3) +4 (x + 3))} \\ = > \frac{x(x + 1)(x + 3)(x + 4)}{(x + 3)(x + 4)} \\ = > x(x + 1) \\ = > {x}^{2} + x$

Hope this answer helps you ^_^ !