Question

(x²-3x)(x²-3x-1)-20 factorize​

Answer 1

Answer:

(x^2-3x)(x^2-3x-1)-20

Let x^2-3x be a ---1

Therefore, according to the problem we get:-

a(a-1)-20=0

a^2-a-20=0

a^2-5a+4a-20=0

a(a-5)+4(a-5)=0

(a+4)(a-5)=0

Replacing the value of a, we get(from 1)

(x^2-3x+4)(x^2-3x-5-1)=0

(x^2-3x+4)(x^2-3x-6)

Hope this helps..☺️☺️

Answer 2

Answer:

(x²+3x+4)(x²+3x-4)

Step-by-step explanation:

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