x²-3x+y²-x-2y² answers
Answers
x = 3+2y
x^2 + 2y^2 = 27
Firstly, we need to align both equations so that they use similar terms, we can create an equation that contains x^2 and y^2 by squaring both sides of x = 3+ 2y
(x)^2 = (3+ 2y)^2
x^2 = 4y^2 + 12y + 9
Then, we can get both equations to parallel each other by altering x^2 + 2y^2 = 27 so that x^2 is alone:
x^2 + 2y^2 = 27 therefore x^2 = -2y^2 +27
No we can subtract one equation from the other:
x^2 = 4y^2 + 12y + 9
x^2 = -2y^2 + 27
Therefore
0 = 6y^2 + 12y - 18
This equation can be simplified by dividing all the elements by 6, leaving:
y^2 + 2y - 3 = 0
This factorises to:
(y + 3)(y - 1) = 0
Which results in two y values: -3 and 1
From these values, you can create two values of x by using the equation x = 3 + 2y:
Let y = -3:
x = 3 + 2(-3)
x = 3 - 6 = -3
This can be verified using the other original equation:
x^2 + 2y^2 = 27
(-3)^2 + 2(-3)^2 = 27
9 + 2(9) = 27
9 + 18 = 27
27 = 27
For the other value:
Let y = 1:
x = 3 + 2y
x = 3 + 2(1)
x = 3 + 2 = 5
Verify:
x^2 + 2y^2 = 27
(5)^2 + 2(1)^2 = 27
25 + 2 = 27
27 = 27
Considering how long it took to type this all out, I won’t do the second equation. Similar steps and processes are used though.
Answer:
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Explanation:
If A= 2y²+3x-x²,B= 3x²-y² and C=5x²-3xy then find i) A+B ii) B+C iv) B-C v) A+B +C vi) A+B -C pls find it na - 15123062. ... (i)A+B(i)A+B. =2y^2+3x-x^2+3x^2-y^2= 2y2+3x−x2+3x2−y2.