x² – 3x² – 9x-5 please answer me
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x³ - 3x² - 9x - 5
= x³ + x² - 4x² - 4x - 5x - 5
= x²(x+1) - 4x(x+1) -5(x+1)
= (x+1)(x² - 4x - 5)
= (x+1)(x² - 5x + x - 5)
= (x+1)[x(x-5) + 1(x-5)]
= (x+1)[(x-5)(x+1)]
= (x+1)(x+1)(x-5)
=(x+1)²(x-5)
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