Question

x²+3xy+y² is question ka answer de do bhai​

Answer 1

Answer:

x²+3xy+y²

the answer will be this cuz they are unlike terms

they can't be added

Answer 2

Step-by-step explanation:

(x

2

+3xy+y

2

)dx−x

2

dy=0

x

2

(x

2

+3xy+y

2

)

=

dx

dy

1+3(

x

y

)+(

x

y

)

2

=

dx

dy

let

x

y

=t−−−−(1)

y = xt

diff. w.r.t x

dx

dy

=t+x

dx

dt

(i)⇒1+3(t)+(t)

2

=t+x

dx

dt

t

2

+2t+1=x

dx

dt

x

dx

=

(t+1)

2

dt

integrating both sides

∫

x

dx

=∫

(t+1)

2

dt

ln∣x∣=

(t+1)

−1

+c

ln∣x∣=

(

x

y

+1)+c

−1

ln∣x∣=

x+y

−x

+c

at x = 1, y = 0

lnl=

1+0

−1

+c

0=−1+c⇒c=1

ln∣x∣=

x+y

−x

+1

I hope this will help you.