Question

X2+3Y2=2XY3 in this reaction 2 moles of X2 and 4.5 moles of Y2 react to give product which is the limiting agent and calculation no of moles of X2,Y2 and XY3 in reaction side

Answer 1

Answer:

let atomic weight of x = Mx

atomic weight of y = My

we know,

mole = weight /atomic weight

a/c to question,

mole of xy2 = 0.1

so,

0.1 = 10g/( Mx +2My)

Mx + 2My = 100g -------(1)

for x3y2 ; mole of x3y2 = 0.05

0.05 = 9/( 3Mx + 2My )

3Mx + 2My = 9/0.05 = 9× 20 = 180 g ---(2)

solve eqns (1) and (2)

2Mx = 80

Mx = 40g/mol

and My = 30g/mole