Question

X2+3Y2=2XY3.In this reaction 2moles of X2 and 4.5moles of Y2 react to give products.which is the limiting agent and calculate no of moles of X2,Y2andXY3 in the reaction mixture?

Answer 1

Answer: 0 moles of Y_2

0.5 moles of X_2

3 moles of XY_3

Explanation:-

The balanced chemical reaction is:

$X_2+3Y_2\rightarrow 2XY_3$

According to stoichiometry:

3 moles of $Y_2$ react with 1 mole of $X_2$

Thus 4.5 moles of  $Y_2$ react with =$\frac{1}{3}\times 4.5=1.5moles$ of $X_2$

$Y_2$  is a limiting reagent as it limits the formation of products and $X_2$ is an excess reagent as (2-1.5)=0.5 moles of $X_2$ are left unreacted.

3 moles of $Y_2$ form 2 moles of $XY_3$

Thus 4.5 moles of $Y_2$ react with =$\frac{2}{3}\times 4.5=3moles$ of $XY_3$

Thus there are 0 moles of $Y_2$ , 0.5 moles of $X_2$ and 3 moles of $XY_3$