Question

X2/4+2x-5 factorise it.....

Answer 1

Given equation

$\dfrac{x^{2} }{4} +2x-5=0$

Multiplying by 4, we get,

$x^{2} +8x-20=0$

Solving, we get,

$x^{2} +8x-20=0\\\implies x^{2} +10x-2x-20 = 0\\\implies x(x+10)-2(x+10)=0\\\implies (x-2)(x+10)=0$

Now,

$x-2=0\\\implies x = 2\\\\x+10=0\\\implies x = -10$

$\boxed{\boxed{\bold{Therefore, \ the \ factorised \ expression \ is \ (x-2)(x+10)}}}}$

                                                         

Answer 2

Answer:

Given equation

\dfrac{x^{2} }{4} +2x-5=0

4

x

2

+2x−5=0

Multiplying by 4, we get,

x^{2} +8x-20=0x

2

+8x−20=0

Solving, we get,

\begin{lgathered}x^{2} +8x-20=0\\\implies x^{2} +10x-2x-20 = 0\\\implies x(x+10)-2(x+10)=0\\\implies (x-2)(x+10)=0\end{lgathered}

x

2

+8x−20=0

⟹x

2

+10x−2x−20=0

⟹x(x+10)−2(x+10)=0

⟹(x−2)(x+10)=0

Now,

\begin{lgathered}x-2=0\\\implies x = 2\\\\x+10=0\\\implies x = -10\end{lgathered}

x−2=0

⟹x=2

x+10=0

⟹x=−10