Question

x2-4√2x+6=0 by factorisation method

Answer 1

Answer:

Step-by-step explanation:

x²-4√2x+6 = 0

=> x²-3√2x-√2x+6 = 0

=> x(x-3√2) - √2(x-3√2) = 0

=> (x-√2) (x-3√2)

Answer 2

The solution is $x=3\sqrt{2},\sqrt2$

Step-by-step explanation:

Given : Quadratic equation $x^2-4\sqrt{2}x+6=0$

To find : Solve by factorization method?

Solution :

Quadratic equation $x^2-4\sqrt{2}x+6=0$

Apply middle term split,

$x^2-3\sqrt{2}x-\sqrt2x+6=0$

$x(x-3\sqrt{2})-\sqrt2(x-3\sqrt{2})=0$

$(x-3\sqrt{2})(x-\sqrt2)=0$

The factor form is $(x-3\sqrt{2})(x-\sqrt2)$

The solution is

$x=3\sqrt{2},\sqrt2$

#Learn more

A³-27 by factorisation method​

https://brainly.in/question/9799376