X2-4√2x+6=0 by using formula
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GIVEn
x² - 4√2x + 6 = 0
Solve it
SOLUTIOn
→ x² - 4√2x + 6 = 0
★ Splitting middle term
→ x² - √3x - 2√3x + 6 = 0
→ x(x - √3) - 2√3(x - √3) = 0
→ (x - √3)(x - 2√3) = 0
Either,
→ (x - √3) = 0
→ x = √3
Or,
→ (x - 2√3) = 0
→ x = 2√3
Hence, √3 and 2√3 are the zeros of given polynomial
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