X²-4✓2x+6 solve this equation by completing square method
Answers
Answered by
0
Answer:
x is 3√2,√2
Step-by-step explanation:
given,
x^2-4√2x+6=0
send 6 to RHS
x^2-4√2= -6
make LHS as perfect square
x^2-2.((2√2))/2.(x)=-6
add (2√2)^2 on both sides and make LHS a perfect square
(x-2√2)^2 = -6 +(2√2)^2
(x-2√2)^2= -6+8
(x-2√2)^2=2
x is +√2+2√2=3√2
x is -√2+2√2=√2
so values of x are 3√2,√2
Similar questions